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c#processlaunchappv

Launch Application Virtualization Client app from C#

I'm writing an application to serve as a launcher for many different apps, some of which are launched using the Microsoft Application Virtualization Client. What is the proper way to start these apps from C#?

I know I can use this:

Process myProcess = new Process(); myProcessStartInfo.FileName = @"C:\Users\path\to\app.lnk"; myProcess.Start();

However, not everyone will have their app.lnk shortcut in the same place. Is there any way to use C# to launch the virtualization client and pass it \launch parameters?

Solution

  • Got this working, here's the code:

    Process myProcess= new Process();
myProcess.StartInfo.FileName = "sfttray.exe";
myProcess.StartInfo.Arguments = "/launch \"name_of_appv5_app\"";
myProcess.Start();

    Mainly just a matter of string formatting and escape sequences!