I have a spring rabbit consumer like:
@Override public void onMessage(Message amqpMessage, Channel channel)
throws Exception {
//..some code goes here - I want it to be in spring transaction
}
The issue is the code which is in onMessage method is not under transaction. I checked it, I save data to 3 tables, then throw exception, then save to 4th table. And data from 3 previos tables is not being rolled back. How to do that properly in spring? I want all code in onMessage method to be within a transaction. Thanks
UPDATE My rabbit conf:
@Configuration @ComponentScan(basePackages = {"com.mycompany"})
public class TicketModeRabbit {
@Bean TicketModeConsumer ticketModeConsumer() {
return new TicketModeConsumer();
}
@Bean(name = TicketModeRabbitData.QUEUE_BEAN_NAME) Queue queue() {
return new Queue(TicketModeRabbitData.QUEUE_BEAN_NAME);
}
@Bean(name = TicketModeRabbitData.QUEUE_BINDING_NAME) Binding binding(
@Qualifier(TicketModeRabbitData.QUEUE_BEAN_NAME) Queue q, TopicExchange e) {
return BindingBuilder.bind(q).to(e).with(TicketModeRabbitData.QUEUE_TOKEN_NAME);
}
@Bean(name = TicketModeRabbitData.CONTAINER_NAME)
SimpleMessageListenerContainer container(ConnectionFactory connectionFactory,
@Qualifier(TicketModeRabbitData.LISTENER_ADAPTED_NAME)
MessageListenerAdapter listenerAdapter) {
return WorkerConfigHelper
.rabbitConfigListenerContainer(connectionFactory, listenerAdapter,
TicketModeRabbitData.QUEUE_BEAN_NAME,
WorkerConfigHelper.GLOBAL_CONCURRENT_CONSUMERS);
}
@Bean(name = TicketModeRabbitData.LISTENER_ADAPTED_NAME)
MessageListenerAdapter listenerAdapter() {
return new MessageListenerAdapter(ticketModeConsumer());
}
}
If your transaction manager is properly set up for your database, the only thing you need to do is add the @Transactiona
l annotation on the onMessage
method. Note that the consumer (MessageListener
) needs to be a bean managed by the Spring
container.
@Override
@Transactional
public void onMessage(Message amqpMessage, Channel channel)
throws Exception {
//..some code goes here - I want it to be in spring transaction
}