Bootstrap-UI - How to use TemplateUrl for a tab view without manipulating the URL?

Question

I'm working on some Bootstrap-UI tabs, but I can't find an instance online that uses templateURL without manipulating the URL of the page. Here's what I'd like to do:

HTML

<uib-tabset active="active">
    <uib-tab ng-repeat="tab in model.tabs" index="$index" heading="{{tab.title}}">
        {{tab.content}}
    </uib-tab>
</uib-tabset>

JS

model.jo = {...} // a gigantic JSON object - needs to be available in the templates.
model.tabs = [
    {
        title: "Visualized",
        content: url('vis.html')
    },
    {
        title: "Pure JSON",
        content: url('json.html')
    }
]

Most of the stuff I found online uses $routeProvider & $locationProvider to doctor up the URL in order to show different tabs, like this one: http://embed.plnkr.co/TMN3KNlS4Dv90SvbTQKJ/. I don't want to do that.

Is there any way to just define the templateUrl like you'd do for a component?

Also, I need my JSON Object, model.jo, in the html pages.

Answer 1

You could use ng-include to render template by using its template URL. The only thing you need to change in your tabs object is, have templateUrl instead of content property.

<uib-tabset active="active">
    <uib-tab ng-repeat="tab in model.tabs" index="$index" heading="{{tab.title}}">
        <div ng-include="tab.templateUrl"></div>
    </uib-tab>
</uib-tabset>

Change tabs object to

model.tabs = [
    {
        title: "Visualized",
        templateUrl: 'vis.html'
    },
    {
        title: "Pure JSON",
        templateUrl: 'json.html'
    }
]

Also, ng-include uses the same controller as the source, so you will be able to access the model, specifically model.jo, in both of those pages. Source: Pass parameter to Angular ng-include