I have the following DataTable:
A B C
----------
A1 B1 C1
A1 B1 C2
A1 B1 C3
A1 B2 C1
A1 B2 C2
----------
I tried to convert it using C# to be in XML format like this:
<Data>
<A>
<lable>A1</lable>
<B>
<lable>B1</lable>
<C>
<lable>C1</lable>
<lable>C2</lable>
<lable>C3</lable>
</C>
<lable>B2</lable>
<C>
<lable>C1</lable>
<lable>C2</lable>
</C>
</B>
</A>
</Data>
I did a deep search and I found something helpful online like this. But that one uses relations, and my data is just one table. I also tried this C# code:
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
using System.Xml.Linq;
using System.Data.SqlClient;
SqlConnection con = new SqlConnection("Integrated Security=SSPI;Persist Security Info=False;Initial Catalog=Files;Data Source=localhost");
con.Open();
SqlCommand cmd = new SqlCommand("select * from MyTable",con);
SqlDataAdapter da = new SqlDataAdapter(cmd);
DataTable DT = new DataTable("Data");
da.Fill(DT);
dataGridView1.DataSource = DT;
con.Close();
string XML = ToXmlFormat(DT, 0);
Console.WriteLine(XML);
public string ToXmlFormat(this DataTable table, int metaIndex = 0)
{
XDocument xdoc = new XDocument(
new XElement(table.TableName,
from column in table.Columns.Cast<DataColumn>()
where column != table.Columns[metaIndex]
select new XElement(column.ColumnName,
from row in table.AsEnumerable()
select new XElement(row.Field<string>(metaIndex), row[column])
)
)
);
return xdoc.ToString();
}
The result was another format which is not nested XML as I explained. see image
How can I convert my table into the XML format I need?
You need to use GroupBy
to group the rows, then select the parts you want into XElements
.
The code below should do what you want:
var xml = new XElement(table.TableName, table.Rows.Cast<DataRow>()
.GroupBy(row => (string)row[0])
.Select(g =>
new XElement(table.Columns[0].ColumnName,
new XElement("label", g.Key),
g.GroupBy(row => (string)row[1])
.Select(g1 =>
new XElement(table.Columns[1].ColumnName,
new XElement("label", g1.Key),
new XElement(table.Columns[2].ColumnName,
g1.Select(row =>
new XElement("label", (string)row[2])
)
)
)
)
)
)
).ToString();
Fiddle: https://dotnetfiddle.net/qEWNvj