Can this be done pointfree?
var joinByKey = R.curry(function(key, model){
return R.assoc(key, R.join(',' ,R.prop(key, model)), model);
});
var input = { a: ['1', '2', '3'] };
var result = joinByKey("a", input); // {"a": "1,2,3"}
Yes, it can be done like this :
const joinByKey = key => R.over(
R.lensProp(key),
R.join(',')
);
const input = { a: ['1', '2', '3'] };
const result = joinByKey("a")(input); // {"a": "1,2,3"}
If you want to use it uncurrified :
const joinByKey = R.curry((key, model) => R.over(
R.lensProp(key),
R.join(',')
)(model));
var input = { a: ['1', '2', '3'] };
joinByKey("a", input); // {"a": "1,2,3"}
The second one works both currified or uncurrified.
I find it more readable than your version, in contrary of what @naomik says ...