According to the Java 7 documentation, the method longValue from class java.math.BigDecimal can return a result with the opposite sign.
Converts this BigDecimal to a long. This conversion is analogous to the narrowing primitive conversion from double to short as defined in section 5.1.3 of The Java™ Language Specification: any fractional part of this BigDecimal will be discarded, and if the resulting "BigInteger" is too big to fit in a long, only the low-order 64 bits are returned. Note that this conversion can lose information about the overall magnitude and precision of this BigDecimal value as well as return a result with the opposite sign.
In what case is it possible?
It is possible whenever the value of the BigDecimal
is larger than what a long
can hold.
Example:
BigDecimal num = new BigDecimal(Long.MAX_VALUE);
System.out.println(num); // prints: 9223372036854775807
System.out.println(num.longValue()); // prints: 9223372036854775807
num = num.add(BigDecimal.TEN); // num is now too large for long
System.out.println(num); // prints: 9223372036854775817
System.out.println(num.longValue()); // prints: -9223372036854775799
System.out.println(num.longValueExact()); // throws: ArithmeticException: Overflow