I have 13-bit strings data in a column, I want to count the number of cells with unique combination of bits. The total number of cells in that column is 209066. I am stuck on how to make it possible. Since, 2^13 = 8192 cells, so that's quite hectic too , to find the unique combinations statistically, and then write in the adjacent cell, how much times that value occurs.
13 Bit String Occurrence
1001111101011
0011111010110
0111110101101
1111101011011
1111010110110
1110101101100
1101011011000
1010110110000
0101101100001
1011011000010
0110110000101
1101100001011
1011000010111
0110000101110
1100001011101
1000010111011
0000101110111
0001011101110
0010111011100
0101110111001
1011101110011
0111011100111
1110111001110
1101110011101
1011100111010
0111001110101
1110011101011
1100111010110
1001110101100
0011101011001
0111010110011
1110101100110
1101011001100
1010110011000
0101100110000
1011001100001
0110011000011
1100110000110
1001100001100
0011000011001
0110000110011
1100001100110
.......
[continued upto cell 209066]
=COUNTIF($A:$A,"="&D1)
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