How does JavaScript treat the ++ operator?

Question

JavaScript does funky automatic conversions with objects:

var o = {toString: function() {return "40"; }};
print(o + o);
print((o+1)+o);
print((o*2) + (+o));

will print:

4040
40140
120

This is because +, if any of the arguments are objects/strings, will try to convert all the arguments to strings then concatenate them. If all arguments are numbers, it adds them together. * and unary + convert objects to numbers using toString (as well as valueOf, not shown here).

What does JavaScript do for the ++ operator?

Answer 1

From ECMAScript Language Specification

11.3 Postfix Expressions

Syntax

PostfixExpression :

• LeftHandSideExpression
• LeftHandSideExpression [no LineTerminator here] ++
• LeftHandSideExpression [no LineTerminator here] --

11.3.1 Postfix Increment Operator

The production PostfixExpression : LeftHandSideExpression [no LineTerminator here] ++ is evaluated as follows:

1. Evaluate LeftHandSideExpression.
2. Call GetValue(Result(1)).
3. Call ToNumber(Result(2)).
4. Add the value 1 to Result(3), using the same rules as for the + operator (section 11.6.3).
5. Call PutValue(Result(1), Result(4)).
6. Return Result(3).

---

This is pseudo javascript code of how postInc works:

function postInc(a) {
  var x = +a; // Converts a to a number, Section 11.4.6 Unary + Operator
  a = x + 1;
  return x;
}

Edit: As mikesamuel said: it's not parseInt. Updated to reflect that.