I have a dataset with 160 columns. Some of these columns contains a lot of NA and #DIV/0! I load the data in the following way:
training = read.csv("training.csv",header = TRUE,na.strings = c("NA","NaN","","#DIV/0!"))
How can I keep only columns that contains values in all rows?
@SRivero's answer works, here is another
set.seed(1234)
dat <- as.data.frame(matrix(runif(100000),1000,10))
dat[sample(1:100,20,replace=TRUE),sample(1:10,3,replace=TRUE)] <- NA
# apply through each column seeing if any are NAs
dat[,sapply(dat,function(x) !any(is.na(x)))]
# Check if both answers give same result
all.equal(dat[,which(sapply(dat,function(x) !any(is.na(x))))],
dat[ , colSums(is.na(dat)) == 0])
[1] TRUE
Though mine is a bit faster
library(microbenchmark)
microbenchmark(dat[,sapply(dat,function(x) !any(is.na(x)))],
dat[ , colSums(is.na(dat)) == 0])
Unit: microseconds
expr min lq mean median uq max neval
dat[, sapply(dat, function(x) !any(is.na(x)))] 87.464 89.7790 94.51491 90.9830 97.124 190.865 100
dat[, colSums(is.na(dat)) == 0] 197.958 199.9585 226.49657 201.4265 207.278 1382.612 100