I have a very simple function to convert a 3 char string representing a bit string to a decimal number:
int bin3_to_dec(char *bin) {
int result;
result=0;
printf("string: %s\n", bin);
printf("c0: %c\n", bin[0]);
printf("c1: %c\n", bin[1]);
printf("c2: %c\n", bin[2]);
if ((strcmp(&bin[0], "1") == 0))
result += 4;
if ((strcmp(&bin[1], "1") == 0))
result += 2;
if ((strcmp(&bin[2], "1") == 0))
result += 1;
printf("result: %d\n", result);
return result;
}
When I run the program and feed this function the string 111
it should calculate 7. Instead it outputs this:
string: 111
c0: 1
c1: 1
c2: 1
result: 1
Why is it not calculating the correct value? Why is only the third condition successfully passing?
Your string bin
equal "111" really consists of four chars - that is '1', '1', '1', '\0' where the 4th char has the value zero which terminates (i.e. ends) the string.
So &bin[0]
is the string "111"
and &bin[1]
is the string "11"
and &bin[2]
is the string "1"
So what your code is actually doing is the same as:
if ((strcmp("111", "1") == 0))
result += 4;
if ((strcmp("11", "1") == 0))
result += 2;
if ((strcmp("1", "1") == 0))
result += 1;
Only the last compare results in true so result
becomes 1