On ubuntu 16.04, i have a directory with these files :
-rw-rw-r-- 1 user0 user0 86 jui 7 21:32 vim html picker.url
-rw-rw-r-- 1 user0 user0 104 jui 7 21:32 cocoonjs build android apk.url
-rw-rw-r-- 1 user0 user0 61 jui 7 21:32 Simple Modal Window - Codepad.url
-rw-rw-r-- 1 user0 user0 96 jui 7 21:32 cocoon.js android build apk+++.url
-rw-rw-r-- 1 user0 user0 44 jui 7 21:32 CodePen - Front End Developer Playground & Code Editor in the Browser (1).url
The file "vim html picker.url" have this information :
--> cat vim\ html\ picker.url
[InternetShortcut]
URL=https://github.com/KabbAmine/vCoolor.vim/blob/master/README.md
what i want to do is open all of theses files from this directory in tab in my chromium-browser.
i have tried this in my gnome-terminal :
chromium-browser *.*
but chrome open the text information : URL=https://github.com/KabbAmine/vCoolor.vim/blob/master/README.md and not the url itself :https://github.com/KabbAmine/vCoolor.vim/blob/master/README.md.
wich command allow my desired behaviour ?
grep "^URL=" *.url | cut -d= -f2 | xargs chromium-browser
should do the trick.
Explanation:
grep "^URL=" *.url
- cut the line beginning with URL=
from each file ending in .url
cut -d= -f2
- split each remaining line into parts delimited by '=' and output the second and all subsequent parts (i.e. the part after the first '=')xargs chromium-browser
- use the list of URLs as arguments to chromium.