Is it possible? if so, how?
The following code is executed in an IEX.
However, the compiled code generates a runtime error.
:ets.fun2ms(fn({a,b}) -> a and b end)
The error comes out like this: I want to know how to properly call.
** (exit) exited in: :ets.fun2ms(:function, :called, :with, :real, :fun, :should, :be, :transformed, :with, :parse_transform, :or, :called, :with, :a, :fun, :generated, :in, :the, :shell)
** (EXIT) :badarg
stacktrace:
(stdlib) ets.erl:554: :ets.fun2ms/1
test/game/ets_lookup_test.exs:27
No, you can't. At least not with "real functions" like the error says. Elixir functions are defined a bit different than the functions in Erlang and that's why this function does not work. Fortunately, you can accomplish the same using this repository https://github.com/ericmj/ex2ms
As it is stated in the README:
iex(1)> import Ex2ms
iex(2)> fun do { x, y } = z when x > 10 -> z end
[{{:"$1",:"$2"},[{:>,:"$1",10}],[:"$_"]}]
iex(3)> :ets.test_ms({ 42, 43 }, v(2))
{:ok,{42,43}}
iex(4)> :ets.test_ms({ 0, 10 }, v(2))
{:ok,false}
The macro Ex2ms.fun/1
does the same as ets:fun2ms/1
.
I hope this helps.