c++11 initializer list as an array

Question

I have the following function

void f(double* arr) 
{ ... }

Is this a sensible way to call that function in C++11: f({10.0, 8.0});? Thanks.

Answer 1

One possible solution is to make a small wrapper around the f function:

void f(double* arr){

}
void f_wrapper(std::vector<double> v){
    f(v.data());    
}
int main(){
  f_wrapper({1.,2.,3.});
}

or as @(Kerrek SB) mentioned:

void f(const double* arr){

}

void f_wrapper(std::initializer_list<double> v){
    f(v.begin());
}

int main(){
   f_wrapper({1.,2.,3.});
}