I have searched the web a bit for this and also found a solution to my problem but I believe it might be possible to reduce the amount of coding necessary. I was hoping you might be able to help me.
I have the following XML and I need to get the value from title by the id. (In this case I am interested in the title "somefile2.jpg" which I need to find by the id of "2")
<entry>
<name></name>
<title type="text">somefile1.jpg</title>
<m:properties xmlns:m="http://schemas.microsoft.com/ado/2007/08/dataservices/metadata" xmlns:d="http://schemas.microsoft.com/ado/2007/08/dataservices">
<d:path></path>
<d:id>1</d:id>
</m:properties>
</entry>
<entry>
<name></name>
<title type="text">somefile2.jpg</title>
<m:properties xmlns:m="http://schemas.microsoft.com/ado/2007/08/dataservices/metadata" xmlns:d="http://schemas.microsoft.com/ado/2007/08/dataservices">
<d:path></path>
<d:id>2</d:id>
</m:properties>
</entry>
<entry>
<name></name>
<title type="text">somefile3.jpg</title>
<m:properties xmlns:m="http://schemas.microsoft.com/ado/2007/08/dataservices/metadata" xmlns:d="http://schemas.microsoft.com/ado/2007/08/dataservices">
<d:path></path>
<d:id>3</d:id>
</m:properties>
</entry>
To solve this I run the following code:
XmlDocument xDoc = new XmlDocument();
xDoc.LoadXml(xmlfile);
XmlNamespaceManager nameSpaceManager = new XmlNamespaceManager(xDoc.NameTable);
nameSpaceManager.AddNamespace("b", "http://www.w3.org/2005/Atom");
nameSpaceManager.AddNamespace("m", "http://schemas.microsoft.com/ado/2007/08/dataservices/metadata");
nameSpaceManager.AddNamespace("d", "http://schemas.microsoft.com/ado/2007/08/dataservices");
//Find the correct XML node by child ID and get it's title
XmlNode parentNode = null;
string incomingID = "2";
foreach (XmlNode node in xDoc.SelectNodes(@"//m:properties/d:id", nameSpaceManager))
{
if (node.InnerText == incomingID)
{
parentNode = node.ParentNode.ParentNode;
break;
}
}
//Add the nodes to a new XML document so it can be traversed
XmlDocument parent = new XmlDocument();
parent.LoadXml("<root>" + parentNode.InnerXml + "</root>");
XmlNamespaceManager parentNameSpaceManager = new XmlNamespaceManager(parent.NameTable);
parentNameSpaceManager.AddNamespace("b", "http://www.w3.org/2005/Atom");
parentNameSpaceManager.AddNamespace("m", "http://schemas.microsoft.com/ado/2007/08/dataservices/metadata");
parentNameSpaceManager.AddNamespace("d", "http://schemas.microsoft.com/ado/2007/08/dataservices");
string xmlFilename = parent.GetElementsByTagName("title")[0].InnerText;
If possible I would like to change the code so I don't create a whole new XmlDocument just to find the title. Do you think it is possible to get the title by some shorter code? I was thinking something in the line of:
string xmlFilename = xDoc.SelectSingleNode(@"//m:properties[id='" + incomingID + "']", nameSpaceManager).ParentNode.ParentNode.FirstChild["title"].InnerText;
If i run the above code it returns an Exception: Objectreference not set to an instance of an object
Omg.. as usual when you've posted a question you find the answer not long after. This was my solution:
string xmlFilename = parentNode["title"].InnerText;
This means I can finally remove the dreadful 2nd XmlDocument. :)