I got a survey data.frame they are 100 columns and each columns have 2 factors - Yes or No. However some survey have answers like, Yes! or Nope or Yay or Nah... which really they are yes or no.
My question is how can I achieve my converting all values in other columns based on their factor level? e.g if factor level is 1 replace text to Yes else No.
My second question is, sometimes I am left with the 3rd level that isn't used, how can I remove all unused factors in ALL columns in data frame. I got more than 100 columns.
We can loop over the columns and replace the levels using %in%
df1[] <- lapply(df1, function(x) {
levels(x)[levels(x) %in% c("Yes!", "Yay")] <- "Yes"
levels(x)[levels(x) %in% c("Nope", "Nah")] <- "No"
x
})
To drop the unused levels we can use droplevels
df2 <- droplevels(df1)
But, based on the assignment we did earlier, it would be taken care off.
df1
# Col1 Col2 Col3
#1 Yes No No
#2 Yes Yes No
#3 No No No
#4 No No No
#5 No Yes No
#6 No No No
#7 Yes Yes No
#8 No Yes No
#9 No No No
#10 Yes Yes No
str(df1)
#'data.frame': 10 obs. of 3 variables:
#$ Col1: Factor w/ 2 levels "No","Yes": 2 2 1 1 1 1 2 1 1 2
#$ Col2: Factor w/ 2 levels "No","Yes": 1 2 1 1 2 1 2 2 1 2
#$ Col3: Factor w/ 1 level "No": 1 1 1 1 1 1 1 1 1 1
set.seed(24)
df1 <- data.frame(Col1 = sample(c("Yes", "Yes!", "Yay", "Nope", "Nah", "No"),
10, replace=TRUE),
Col2 = sample(c("Yes", "Yes!", "Yay", "Nope", "Nah", "No"), 10, replace=TRUE),
Col3 = sample(c("Nope", "Nah", "No"), 10, replace=TRUE)
)