So basically, I have a OpenFileDialog where the user will select a location.
I made it so it would display the directory in a textbox.
But what I want is have another button which would take that directory and start it by using ProcessStartInfo
.
OpenFileDialog, showing it in TextBox:
public void button4_Click(object sender, EventArgs e)
{
OpenFileDialog ofd = new OpenFileDialog();
ofd.Title = "Open Arma 3";
ofd.Filter = "EXE file|*.exe";
if (ofd.ShowDialog() == System.Windows.Forms.DialogResult.OK)
{
textBox1.Text = ofd.FileName;
}
}
Process:
private void button3_Click(object sender, EventArgs e)
{
ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.FileName = //RESULT OPENFILEDIALOG SHOULD BE HERE
startInfo.Arguments = @"-window -useBE -mod=e:\Aaron\Addons\@CBA_A3";
Process.Start(startInfo);
}
Since you already save the result of the OpenFileDialog in textBox1, you can easily access it in the button3_Click event handler.
To fill the startInfo.FileName:
*I added an extra IsNullOrWhiteSpace check, so the application doesn't start another process if the textBox1.Text is empty.
if(!string.IsNullOrWhiteSpace(textBox1.Text)
{
ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.FileName = textBox1.Text
startInfo.Arguments = @"-window -useBE -mod=e:\Aaron\Addons\@CBA_A3";
Process.Start(startInfo);
}