How do I create two table views in one view controller with two custom UITableViewCells?

Question

I am trying to create two UITableViews in one view controller using two custom UITableViewCells. I have the following:

func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
    if tableView == self.tableView {
        let cell = tableView.dequeueReusableCellWithIdentifier("CustomOne") as! CustomOneTableViewCell
        return cell
    }

    if tableView == self.autoSuggestTableView {
        let cell = tableView.dequeueReusableCellWithIdentifier("CustomTwo") as! CustomTwoTableViewCell
        return cell
    }
}

But I keep getting the error:

Missing return in a function expected to return 'UITableViewCell'

What do I have to return in the end of the method?

Answer 1

The error appears because if for any reason, the table view is non of the two options that you wrote, then it doesn't have any value to return, just add a default value at the end:

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
    if tableView == firstTableView,
        let cell = tableView.dequeueReusableCell(withIdentifier: "CustomOne") as? CustomOneTableViewCell {
        return cell
    } else if tableView == autoSuggestTableView,
        let cell = tableView.dequeueReusableCell(withIdentifier: "CustomTwo") as? CustomTwoTableViewCell {
        return cell
    }

    return UITableViewCell()
}

Updated to swift 4.1.2: I've updated this answer to version 4.1.2, also, because the return value of the method cannot be nil, modified to a default, dummy UITableViewCell.