Its possible to filter and continue emiting itens like below ?
My code that calls subscriber 2 times:
Observable<Map.Entry<String, ArrayList<MockOverview>>> requestEntries =
this.requestView.request(request)
.map(HashMap::entrySet)
.flatMapIterable(entries -> entries);
requestEntries.filter(entry -> entry.getKey().equals("featured"))
.map((Func1<Map.Entry<String, ArrayList<MockOverview>>, List<MockOverview>>) Map.Entry::getValue)
.subscribe(mockOverviews -> {
Log.i("subscrive", "featured");
});
requestEntries.filter(entry -> entry.getKey().equals("done"))
.map((Func1<Map.Entry<String, ArrayList<MockOverview>>, List<MockOverview>>) Map.Entry::getValue)
.subscribe(mockOverviews -> {
Log.i("subscrive", "featured");
});
What i want:
requestEntries.filter(entry -> entry.getKey().equals("featured"))
.map((Func1<Map.Entry<String, ArrayList<MockOverview>>, List<MockOverview>>) Map.Entry::getValue)
.subscribe(mockOverviews -> {
})
.filter(entry -> entry.getKey().equals("done"))
.map((Func1<Map.Entry<String, ArrayList<MockOverview>>, List<MockOverview>>) Map.Entry::getValue)
.subscribe(mockOverviews -> {
});
You can use doOnNext
in the place of the first subscribe()
requestEntry.filter(v -> ...)
.map(v -> ...)
.doOnNext(v -> ...)
.filter(v -> ...)
.map(v -> ...)
.subscribe(...)
or use publish(Func1)
:
requestEntry.filter(v -> ...)
.map(v -> ...)
.publish(o -> {
o.subscribe(...);
return o;
})
.filter(v -> ...)
.map(v -> ...)
.subscribe(...)