Try-Catch sum two numbers

Question

I'm working on Exception Handling and making a new Java Project.Program waits for user type 2 numbers from keyboard. If user types two integer numbers it'll sum these numbers. If user doesn't type numbers program will print 'Type numbers!' on screen. Here's What I Tried:

public static void main(String[] args) {
    int a = 0;
    int b = 0;
    System.out.println("Type two numbers");
    Scanner scan = new Scanner(System.in);
    try {
        a = scan.nextInt();
        b = scan.nextInt();
    } catch (Exception ex) {
        System.err.println("Type number!");
    }
}

Answer 1

Try code below. It should work as you expect:

public static void main(String[] args) {
    System.out.println("Type two numbers");
    sum();
}

private static void sum(){
    int a = 0;
    int b = 0;
    Scanner scan = new Scanner(System.in);
    try {
        a = scan.nextInt();
        b = scan.nextInt();
        System.out.println(a+b);
    } catch (Exception ex) {
        System.err.println("Type numbers in correct format!");
        sum();
    }
}