Why this code is returning undefined?

Question

var rarr = [];
var reverseArray = function(arr) {
  if(arr[0]) {
     rarr.push(arr[arr.length-1]);
     arr.pop();
     reverseArray(arr);
  } else {
    return rarr;
  }
}

console.log(reverseArray(["A", "B", "C"]));

While debugging value of rarr is ['C','B','A'] at the end, instead it is returning undefined. Thanks in advance.

Answer 1

While debugging value of rarr is ['C','B','A'] at the end, instead it is returning undefined

You are not returning the value that will be returned by recursive calls

replace

reverseArray(arr);

with

return reverseArray(arr);

Or simply

console.log(["A", "B", "C"].reverse());