%edx
has a value of 0x3
, and %eax
has a value of 0x100
.
Then we have the instruction: subl %edx, %eax
What's the result value of %eax
?
You have
movl $3, %edx
movl $0x100, %eax
as input values. The instruction
subl %edx, %eax
just subtracts 3(dec) in EDX from 100(hex) in EAX resulting in 100h-3h=0FDh
.