ostream and istream overlaloading without << / >> operator

Question

Whenever I use cout and cin, I have to use 3 key (shift,2 press < <) .

I tryed to overloading ostream and istream with , (comma operator) .

And now everything works well, except cin on int,float,double,char but it works with char[]. also I tested tie() method to tie ostream to istream but stream of cin does not tie to stream of cout.

In fact cin get value but the value does not tie to cout.

thanks so much if you have an idea.

#include <iostream>

using std::cout;
using std::cin;
using std::endl;


template < class AT> // AT : All Type 
std::ostream& operator,(std::ostream& out,AT t)
{
    out<<t;
    return out;
}
template < class AT> // AT : All Type 
std::istream& operator,(std::istream& in,AT t)
{
    in>>t;
    return in;
}

int main(){
    cout,"stack over flow\n";
    const char* sof ( "stack over flow\n" );
    cout,sof;

    char sof2[20] ("stack over flow\n");
    cout,sof2;

    int i (100);
    float f (1.23);
    char ch ('A');
    cout,"int i = ",i,'\t',",float f = ",f,'\t',",char ch = ",ch,'\n';
    cout,"\n_____________________\n";
    cin,sof2;  /// okay, it works
    cout,sof2; /// okay, it works
    cin,i;     /// okay it works
    cout,i;    /// does not work. does not tie to cin
}

output

stack over flow
stack over flow
stack over flow
int i = 100   ,float f = 1.23 ,char ch = A

_____________________
hello // cin,sof2;  /// okay, it works
hello
50   // cin,i;     /// okay it works
100  // does not work and return the first value the smae is 100


Process returned 0 (0x0)   execution time : 15.586 s
Press ENTER to continue.

by : g++ 5.2.1.

if you wnat to test this code, your gun c++ must be 5.2 or upper; or change () initialize to =

for compile on command-line

g++ -std=c++14 -O2 -Wall -pedantic -pthread main.cpp

Answer 1

You code doesn't work for int, float, double, char because in your >> operator you pass argument by value, not by reference. Change it in this way:

template < class AT> // AT : All Type 
std::istream& operator,(std::istream& in, AT& t)
{
    in>>t;
    return in;
}

But as graham.reeds already stated, it's a bad idea to replace << and >> operators with comma in this way, it will mess your code.