This is a link generated from Google Alerts, and I would like to get where you get redirected. So I need the URL and I would have to retrieve it with Java. I have checked for the response, but no location header redirect.
Maybe something like this:
String URL = "https://www.google.com/url?rct=j&sa=t&url=http://naija247news.com/2016/03/nigerian-bond-yields-rise-after-cbns-interest-rate-hike-aimed-at-luring-investors/&ct=ga&cd=CAIyGjA3ZmJiYzk0ZDM0N2U2MjU6Y29tOmVuOlVT&usg=AFQjCNGs7HsYSodEUnECfdAatG6KgY18DA";
String subStr = URL.substring(URL.indexOf("url=") + 1, URL.indexOf("&ct"));
I forgot what the starting and ending position has to be exactly, which indexes. So you would have to verify that and check it creates a substring at the right position. But the basic idea is to cut out the URL you need and nothing more. This is an example for what you forwarded. It could be that you would have to search for something else to know the end of the substring, when you have a different URL (in the provided example I look for &ct, which maybe be not be the case in another URL). You will have to look up several URLs you have to know how to cut out the URL.