Assigning one character array to another gives Error. Why?

Question

Name of an array is pointer to the first element. So Why one character array cannot be assigned another array ?

#include<stdio.h>
int main()
{
  char str1[]="Hello";
  char str2[10];
  char *s="Good Morning";
  char *q;
  str2=str1;  /* Error */
  q=s; /* Works */
  return 0;
}

Answer 1

Arrays in expressions automatically converted to pointer pointing to the first element of the array except for operands of sizeof operator and unary & operator, so you cannot assign to arrays.

Adding #include <string.h> to the head of your code and using strcpy() is one of good ways to copy strings.

#include<stdio.h>
#include<string.h>
int main(void)
{
  char str1[]="Hello";
  char str2[10];
  char *s="Good Morning";
  char *q;
  strcpy(str2, str1);  /* Works */
  q=s; /* Works */
  return 0;
}