How do you compare two char arrays with each other to see if the inputted one has more than one specific variable than the other?

Question

Okay, so I'm coding a program that will tell the user if the word they put into the command line is an isogram or not, and I'm having difficulties.

How exactly do I go about making it to where the user inputted char array is compared against the other to see if it has more than one letter than the other?

I have this and I'm confused where to go from here.

char[] alphabet = new char[]{'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'};
char[] wordLetters = word.toCharArray(); 
boolean blnResult = Arrays.equals(alphabet,wordLetters);

I'm sure I went in the completely wrong way with this, but how should I go about comparing the two to get that result?

Answer 1

if I understand your problem right this is how I would do it:

String isogram = "salad";
boolean isIsogram = !isogram.matches( ".*(.).*\\1.*" );
System.out.println( isIsogram );

or inefficient but if you have to use arrays:

String isogram = "salad";
boolean isIsogram = true;
for ( int i = 0; i < isogram.length(); i++ ) {
    for ( int j = 0; j < isogram.length(); j++ ) {
        if ( i != j && isogram.charAt( i ) == isogram.charAt( j ) && ( Character.isLetter( isogram.charAt( i ) ) ) ) {
            isIsogram = false;
        }
    }
}
System.out.println( isIsogram );