strange result with operators precedence in C

Question

I just have simple question, I am aware of C language, A while ago i came across this piece of code:

int a;
a=12/8*8;

I tried it using codeblocks and result was that a=8 !!!!!
How did the compiler deal with that?

Thanks.

Answer 1

Due to operator precedence ( * and / have same precedence) and associativity (they have left to right associativity)

12/8*8 is equal to (12/8)*8

Due to integer division

(12/8)*8 is equal to (1)*8

Hence, the final value is 8.