I'm trying to figure out how to get the current timestamp using the function below but I want to format it so that it displays the time like 4:30:23 on output. Eventually I want to subtract the time stamps before and after I run an algorithm.
struct timeval FindTime() {
struct timeval tv;
gettimeofday(&tv,NULL);
return tv;
}
int main() {
printf("%ld\n",FindTime());
return0;
}
Current output format: 1456178100
Could be this what you need?
#include <time.h>
#include <stdlib.h>
#include <unistd.h>
#include <stdio.h>
struct setClock{
int hour;
int minutes;
int seconds;
};
struct setClock currTime(void);
void timeCheck(struct setClock myClock[2]);
int main(void){
struct setClock myClock[2];
myClock[0] = currTime();
printf("Start Time: %d:%d:%d\n\n", myClock[0].hour, myClock[0].minutes, myClock[0].seconds );
sleep(5);
/* CODE HERE */
myClock[1] = currTime();
printf("End Time: %d:%d:%d\n", myClock[1].hour, myClock[1].minutes, myClock[1].seconds );
timeCheck(myClock);
return 0;
}
struct setClock currTime(void){
struct setClock ret;
struct tm *tm;
time_t myTime;
myTime=time(NULL);
tm=localtime(&myTime);
ret.hour = tm->tm_hour;
ret.minutes = tm->tm_min;
ret.seconds = tm->tm_sec;
return ret;
}
void timeCheck(struct setClock myClock[2]){
int hour;
int minute;
int second;
time_t end, start;
double diff;
start = (time_t)((myClock[0].hour * 60 + myClock[0].minutes) * 60 + myClock[0].seconds) ;
end = (time_t)((myClock[1].hour * 60 + myClock[1].minutes) * 60 + myClock[1].seconds) ;
if( end < start ){
end += 24 * 60 * 60 ;
}
diff = difftime(end, start);
hour = (int) diff / 3600;
minute = (int) diff % 3600 / 60;
second = (int) diff % 60;
printf("\n\n");
printf("The elapsed time is %d Hours - %d Minutes - %d Seconds.\n", hour, minute, second);
}
Output:
Start Time: 23:19:18
End Time: 23:19:23
The elapsed time is 0 Hours - 0 Minutes - 5 Seconds