How can I return an array of strings in an ANSI C program?

Question

How can I return an array of strings in an ANSI C program?

For example:

#include<stdio.h>

#define SIZE 10

char ** ReturnStringArray()
{
    //How to do this?
}

main()
{
    int i=0;

    //How to do here???

    char str ** = ReturnStringArray();

    for(i=0 ; i<SIZE ; i++)
    {
        printf("%s", str[i]);
    }
}

Answer 1

You could do the following. Error checking omitted for brevity

char** ReturnStringArray() {
  char** pArray = (char**)malloc(sizeof(char*)*SIZE);
  int i = 0;
  for ( i = 0; i < SIZE; i++ ) {
    pArray[i] = strdup("a string");
  }
  return pArray;
}

Note that you'd need to correspondingly free the returned memory.

Additionally in your printf call you'll likely want to include a \n in your string to ensure the buffer is flushed. Otherwise the strings will get queued and won't be immediately printed to the console.

char** str = ReturnStringArray();
for(i=0 ; i<SIZE ; i++)
{
    printf("%s\n", str[i]);
}