That's my code. What i'm trying to do here is a code that Asks for a name ( like a pass ) if the name is wrong, then the program says those 3 error messages and asks the name again, until one of the 2 white-listed names is given, then just keep going with the code.
int main(void)
{
setlocale(LC_ALL, "Portuguese");
string Name = "";
cout << "Whats your name dude ?" << endl;
cin >> Name;
if (Name == "ighor" ||
Name == "indio")
{
cout << "Welcome friend =D" << endl;
system("pause");
system("cls");
}
else
{
do
{
cout << "Sorry, wrong name =[" << endl;
system("pause");
system("cls");
cout << "I'll give you another chance =]" << endl;
system("pause");
system("cls");
cout << "Write your name again" << endl;
cin >> Name;
if (Name == "ighor" ||
Name == "indio")
{
continue;
}
} while (Name != "ighor" ||
Name != "indio");
}
cout << "Whats up" << Name << endl;
system("pause");
system("cls");
return 0;
}
My tests with this code gave me this :
If i put a white-listed name ( indio or ighor ) i get the massage of correct name
"Welcome friend =]".
If i put a wrong name, i get the massage of wrong name, nice, then i'm asked to enter the name again, i put one of the white-listed names and it keeps saying that it's the wrong name, wrong names also show wrong name message.
The logic in the do-while loop is flawed. Instead of
continue;
you need
break;
continue; continues with the next iteration of the loop. break; breaks the loop.
Also, the while statement logic incorrect. You need to use:
while (Name != "ighor" && Name != "indio");
^^^ not ||
Having said that, you only need one of the checks, not both.
You can use:
do
{
...
if (Name == "ighor" || Name == "indio")
{
break;
}
} while (true);
or
do
{
...
} while (Name != "ighor" && Name != "indio");