I'm trying to find whether a given number (Input by user) is even or odd.
I'm simply applying
AND
operation on binary digits of a no. with1
, If the number is odd then operation will result0
and we will Output Number is odd, otherwise we will output Number is even.
Although logic seems simple, But it's not working in the below code. I'm not getting where is the problem in the code. Can anybody tell me where is the problem
section .data
userMsg db 'Please enter a number'
lenuserMsg equ $ - userMsg
even_msg db 'Even Number!'
len1 equ $ - even_msg
odd_msg db 'Odd Number!'
len2 equ $ - odd_msg
section .bss
num resb 5 ;Reserved 5 Bytes for Input
section .text
global _start ;must be declared for linker (gcc)
_start:
;User Prompt
mov ebx, 1 ;file descriptor (stdout)
mov ecx, userMsg ;message to write 'Please enter a number'
mov edx, lenuserMsg ;message length
mov eax, 4 ;system call number (sys_write)
int 0x80 ;call kernel
;Taking user input
mov ebx, 0 ;(stdin)
mov ecx, num
mov edx, 5 ;i/p length
mov eax, 3 ;system call number (sys_read)
int 0x80 ;call kernel
mov ax, [num]
and ax, 1
jz evnn ;Jump on Even
;Printing No. is Odd
mov ebx, 1 ;file descriptor (stdout)
mov ecx, odd_msg ;message to write 'Odd Number!'
mov edx, len2 ;message length
mov eax, 4 ;system call number (sys_write)
int 0x80 ;call kernel
jmp outprog ;Jump to exit
;Printing No. is Even
evnn:
mov ebx, 1 ;file descriptor (stdout)
mov ecx, even_msg ;message to write 'Even Number!'
mov edx, len1 ;message length
mov eax, 4 ;system call number (sys_write)
int 0x80 ;call kernel
;Exit
outprog:
mov eax, 1 ;system call number (sys_exit)
int 0x80 ;call kernel
Your code does not work because when you ask the user for a number, you read in an ASCII encoded string. You will need to call atoi
(ASCII to INT) first to convert the string to a "real" number as computers see it. atoi
is included in glibc.
extern atoi
push eax ; pointer to your string to be converted, eg '123'
call atoi
; now eax contains your number, 123
You can also do a bit test on the least significant bit (bit 0) to find out if it is even or odd:
mov al, 01000_1101b
bt al, 0 ; copies the bit to the Carry Flag
jc its_odd ; jump if CF==1
; else - it's even (CF==0)
What BT does, it copies the bit to CF and you can do conditional jumps based on that.