Most time efficient way to remove stop words in Java from an array of strings

Question

How do I remove these stopwords in the most efficient way. The approach below doesn't remove the stopwords. What am I missing?

Is there any other way to do this?

I want to accomplish this in the most time efficient way in Java.

public static HashSet<String> hs = new HashSet<String>();


public static String[] stopwords = {"a", "able", "about",
        "across", "after", "all", "almost", "also", "am", "among", "an",
        "and", "any", "are", "as", "at", "b", "be", "because", "been",
        "but", "by", "c", "can", "cannot", "could", "d", "dear", "did",
        "do", "does", "e", "either", "else", "ever", "every", "f", "for",
        "from", "g", "get", "got", "h", "had", "has", "have", "he", "her",
        "hers", "him", "his", "how", "however", "i", "if", "in", "into",
        "is", "it", "its", "j", "just", "k", "l", "least", "let", "like",
        "likely", "m", "may", "me", "might", "most", "must", "my",
        "neither", "n", "no", "nor", "not", "o", "of", "off", "often",
        "on", "only", "or", "other", "our", "own", "p", "q", "r", "rather",
        "s", "said", "say", "says", "she", "should", "since", "so", "some",
        "t", "than", "that", "the", "their", "them", "then", "there",
        "these", "they", "this", "tis", "to", "too", "twas", "u", "us",
        "v", "w", "wants", "was", "we", "were", "what", "when", "where",
        "which", "while", "who", "whom", "why", "will", "with", "would",
        "x", "y", "yet", "you", "your", "z"};
public StopWords()
{
    int len= stopwords.length;
    for(int i=0;i<len;i++)
    {
        hs.add(stopwords[i]);
    }
    System.out.println(hs);
}

public List<String> removedText(List<String> S)
{
    Iterator<String> text = S.iterator();

    while(text.hasNext())
    {
        String token = text.next();
        if(hs.contains(token))
        {

                S.remove(text.next());
        }
        text = S.iterator();
    }
    return S;
}

Answer 1

You shouldn't manipulate the list while iterating over it. Moreover, you're calling next() twice under the same loop that evaluates hasNext(). Instead, you should use the iterator to remove the item:

public static List<String> removedText(List<String> s) {
    Iterator<String> text = s.iterator();

    while (text.hasNext()) {
        String token = text.next();
        if (hs.contains(token)) {
            text.remove();
        }
    }
    return s;
}

But that's a bit of "reinventing the wheel", instead, you could just use the removeAll(Collcetion) method:

s.removeAll(hs);