I'm attempting to use browser-sync with Gulp 4, but bs is not preserving state, and instead does a full refresh. This is not very useful. It seems bs no longer supports true injection. I filed an issue on GH if you want to contribute.
Here is the pertinent code:
// styles:dev task
gulp.task('styles:dev', function() {
return gulp.src(config.src)
.pipe(sourcemaps.init())
.pipe(postcss(config.postcss.dev))
.pipe(sourcemaps.write('.'))
.pipe(gulp.dest(config.dest.dev))
.pipe(browserSync.stream());
});
// browserSync task
gulp.task('browserSync', function(cb) {
browserSync.init(config, cb);
});
// Watch task:
gulp.task('watch:styles', function() {
return gulp.watch(config.paths.css,
gulp.series('styles:dev'));
});
gulp.task('watch', gulp.parallel('watch:styles'));
// default task
gulp.task('default',
gulp.series('clean:dev',
gulp.parallel('copy:dev', 'styles:dev'), 'browserSync', 'watch')
);
Thanks in advance.
Fixed. Here's where I went wrong:
The browser-sync constructor takes an options object, which can include a files
array. Most of the tutorials I've read, including the gulpfile for Google's very own Web Starter Kit, do not include this. As it turns out, this is required for style injection to preserve state.
Furthermore, do not pass .stream()
or .reload()
as the final pipe in your styles task. It is not needed, and will short circuit style injection, forcing a full refresh.
Finally, the browserSync
process must not be terminated, and watch
and browserSync
tasks must execute in parallel in order for live style injection to take place.
Hope this helps anybody facing this issue.
I also closed the corresponding github issue, and posted my gulpfile