find all input and select without prop disabled

Question

I want to select all the input and select with a class disabled with out the property disabled. I will use this for validation purposes.

var disabled3 = $('#table').find('input,select').is(':not(:disabled)').hasClass('disabled');

tried above but not working

var disabled3 = false;
console.log(disabled3);
if ($('#table').find('input,select').is(':not(:disabled)')) {
    disabled3 = $('#table').find('input,select').hasClass('disabled');
}


if (disabled3) {
    alert('Missing somefields')
    return false;
}

Answer 1

You can use

$('#table').find('input.disabled,select.disabled').not(":disabled" )

Also note that it will return a jquery object. Which means your if condition would be always true. Use length property to get the count of the objects and use that inside the if condition.

disabled3 = $('#table').find('input.disabled,select.disabled').not(":disabled" ).length;
if (length > 0) {
  alert('Missing somefields')
  return false;
}