Search code examples
phpajaxcodeignitercodeigniter-3codeigniter-2

Search an id and place data corresponding to that id in the same page using codeigniter and ajax.the data cannot place to the fields


the data corresponding to the id is getting.but cannot place to the text fields. i want to place data corresponding to that id in the text fields.anybody can help.its not getting Controller

 public function addrfqoffline() {
        $this->load->helper(array('form', 'url'));
        $this->load->view('moderator/templates/header');
        $this->load->view('moderator/templates/sidebar');
        $rid=$this->input->post('reqid');
         echo $rid;
      $requirement=$this->requirement_model->viewdata($rid);
      $data['customers']=$this->userdata->usersname();
        $data['merchants']=$this->merchant_model->merchantname();
       // $data['mroproducts']=$this->mroproduct_model->mroproductname();
        $data['units']=$this->requirement_model->fetchunits();

        if($requirement)
      {
           foreach ($requirement as $reqdata) {
                $dat['reqid'] = $reqdata->rqm_id;
                $dat['service'] = $reqdata->rqm_service;
               $this->load->view('moderator/mrorfqnew',array_merge($dat,$data));
           }

      }
        $this->load->view('moderator/mrorfq',$data);
            $this->load->view('moderator/templates/footer');
}

view

   <div class="col-xs-6">
        <label for="txtname">Title of Quotation Request :</label>
        <input type="text" name="txtTitle" class="form-control" id="txtname"  value="<?php if(!empty($reqid)){echo $reqid;} ?>" required>
   </div>`enter code here`

model

public function viewdata($reqid) {
      $this->db -> select('*');
        $this -> db -> from('jil_requirements');
    $this -> db -> where('rqm_id',$reqid);
    $query = $this -> db -> get();
         return $query->result();
}

ajax

<script>
function getValue(val) {
  //alert(val);
    $.ajax({
    type: "POST",
    url: "<?php echo base_url()?>moderator/RFQ/addrfqoffline",
    data:'reqid='+val,
    success: function(data){
             alert(data);
        $("#txtproduct").html(data);
    }
    });
}
</script>

Solution

  • First create an empty div in the page where you want to display the content.

     <div id="content"></div>
    

    Next, change your controller function like this

    function addrfqoffline() {
        $content = "";
        $this->load->helper(array('form', 'url'));
        $content = $this->load->view('moderator/templates/header','',true);
        $content .= $this->load->view('moderator/templates/sidebar','',true);
        $rid = $this->input->post('reqid');        
        $requirement = $this->requirement_model->viewdata($rid);
        $data['customers'] = $this->userdata->usersname();
        $data['merchants'] = $this->merchant_model->merchantname();
        // $data['mroproducts']=$this->mroproduct_model->mroproductname();
        $data['units'] = $this->requirement_model->fetchunits();
    
        if ($requirement) {
            foreach ($requirement as $reqdata) {
                $dat['reqid'] = $reqdata->rqm_id;
                $dat['service'] = $reqdata->rqm_service;
                $content .= $this->load->view('moderator/mrorfqnew', array_merge($dat, $data),true);
            }
        }
        $content .= $this->load->view('moderator/mrorfq', $data,true);
        $content .= $this->load->view('moderator/templates/footer',true);
        echo $content;// this will echo the view here
    }
    

    Now in ajax success,

    success: function(data){
        $("#content").html(data);
    }
    

    This should help you.