What does this code do, and what does it look like in C?

Question

I'm using IDA to disassemble a file, and one of the sections contained this. What is this doing? What would it look like in C?

I believe it pushes edx onto the stack, and converts it to an integer using _atoi, but what is left in eax after that, and why is it comparing it to 5?

mov     ecx, [ebp+argv]
mov     edx, [ecx+4]
push    edx             ; char *
call    _atoi
add     esp, 4
mov     [ebp+var_60], eax
cmp     [ebp+var_60], 5
jle     short loc_401167

Answer 1

The C code would look like this

int var_60;
if ( (var_60 = atoi( argv[1] )) > 5 )
{
    // execute the instructions after the 'jle' instruction, e.g.
    printf( "Invalid argument\n" );
    exit( 1 );
}

In other words, the code checks that the first argument to the program is a number that's less than or equal to 5. It also saves the converted value for later use.