function func() {}
func.prototype.foo = "Var"
console.log(func.foo) // undefined
var foonew = new func()
console.log(foonew.foo) // Var
Why is func.foo unable to lookup the prototype property??
function func() {}
func.__proto__.foo = "Var"
console.log(func.foo) // Var
var foonew = new func()
console.log(foonew.foo) // undefined
When using the proto reference to the prototype it looks like the behavior is reversed.
You are confusing the [[Prototype]] with the prototype.
The [[Prototype]], also known as __proto__, is an internal property which determines from which object the current object should inherit from.
The prototype is a property of constructors which determines the [[Prototype]] of newly created instances.
This is fully explained in __proto__ VS. prototype in JavaScript.
You can achieve both behaviors by setting the [[Prototype]] of the constructor to its prototype. You can use setPrototypeOf (or __proto__) for that:
function func() {}
Object.setPrototypeOf(func, func.prototype);
func.prototype.foo = "Var";
func.foo; // "Var"
new func().foo; // "Var"
I don't recommend it, though.