How do I get the full path of everywhere a JSON field occurs using FasterXML?

Question

Given a JSON field name such as "my_field" and a FasterXML JSON ObjectNode, how can I walk through the JSON and get the fully qualified path of everywhere that "my_field" occurs in the JSON?

"top_field": {
        "mid_field": [
            {
                "my_field": true,
            },
            {
                "my_field": true,
            }
        ],
        "another_mid_field": [
            {
                "my_field": false
            }
        ]
    }

I would want to have the following results:

 top_field.mid_field[0].my_field
 top_field.mid_field[1].my_field
 top_field.another_mid_field.my_field

Is there a part of the FasterXML library that exposes this information without having to parse all the values of the JSON? I was previously using recursion to do so, starting from the root top_field and walking down, passing each object down as I went but that is prone to stack overflows on large JSON objects.

Answer 1

This main:

package jsonpath;

import java.util.List;

import com.jayway.jsonpath.Configuration;
import com.jayway.jsonpath.Option;
import static com.jayway.jsonpath.JsonPath.*;

public class GetPaths {

    public static void main(String [] args) {
        String json = "{\"top_field\": { \"mid_field\": [ { \"my_field\": true, }, { \"my_field\": true, } ], \"another_mid_field\": [ { \"my_field\": false } ] }}";

        Configuration conf = Configuration.builder().options(Option.AS_PATH_LIST).build();
        List<String> pathList = using(conf).parse(json).read("$..my_field");
        for(String path : pathList) {
            System.out.println(path);
        }
    }
}

Will output exactly

$['top_field']['mid_field'][0]['my_field']
$['top_field']['mid_field'][1]['my_field']
$['top_field']['another_mid_field'][0]['my_field']

If you do some simple string replace on that one I think it´s a nice and easy solution. I`m not sure if you can get anything similar with plain Jackson/FasterXML. JsonPath uses Jackson under the hood.