I have a structure
typedef struct myStruct_st
{
int a;
}myStruct;
It can be created using
myStruct * myStruct_new()
{
printf("Allocate\n");
return new myStruct;
}
And deleted using
static void myStruct_free(myStruct * ptr)
{
printf("Deallocate\n");
delete ptr;
}
I want the memory allocated for the structure freed automatically
To this end, I wrote a template
template <class T>
class scoped_del
{
public:
scoped_del(T * p, void (*mfree)(T *)) :
p_(p),
mfree_(mfree)
{
}
~scoped_del()
{
mfree_(p_);
}
private:
T * p_;
void (*mfree_)(T *);
};
And use it like that
int main()
{
myStruct * st = myStruct_new();
class scoped_del<myStruct> ptr_st(st, myStruct_free);
return 0;
}
How can I make it a more standard way using stl or boost?
Boost's shared_ptr does pretty much the same thing, in pretty much the same code.
#include <boost/shared_ptr.hpp>
main() {
boost::sshared_ptr<myStruct> ptr_st(myStruct_new(), myStruct_free);
ptr_st->a = 11;
}
But you should consider whether you want to be writing C++ code or C code. You're using some very C-style syntax (typdef struct
, class
in front of declarations, using a "new function" instead of a constructor, using a "free function" instead of a destructor), but you tagged this C++ and clearly you are using some C++ features. If you want to use C++, use all of it's features, and if you don't want to do that then stick with C. Mixing the two too much is going to cause a lot of confusion for anyone trying to figure out your code (and your "design decisions").