I'm trying to gather data from multiple sheets in a selected workbook. I'm using the following code:
Sub Multiplesheet()
Dim filepath As Variant
Dim outputFilePath As String
Dim outputSheetName As String
Dim sql As String
Dim wbk As Workbook, wks As Worksheet
Dim rng As Excel.Range
Dim sheetname As Variant
'To which file and sheet within the file should the output go?
outputFilePath = "C:\Users\z003k50s\Desktop\Test\Output.xlsx"
outputSheetName = "Sheet1"
For Each filepath In Application.GetOpenFilename(FileFilter:="Excel Files (*.xl*), *.xl*", MultiSelect:=True)
Set schema = conn.OpenSchema(adSchemaTables)
For Each sheetname In schema.GetRows(, , "TABLE_NAME") 'returns a 2D array of one column
sql = sql & _
"UNION ALL SELECT F1 " & _
"FROM [" & sheetname & "]" & _
"IN """ & filepath & """ ""Excel 12.0;"""
Next
Next
sql = Mid(sql, 5) 'Gets rid of the UNION ALL from the first SQL
Dim conn As New ADODB.Connection
Dim rs As ADODB.Recordset
With conn
.Provider = "Microsoft.ACE.OLEDB.12.0"
.ConnectionString = "Data Source=""" & filepath & """;" & _
"Extended Properties=""Excel 12.0;HDR=No"""
.Open
Set rs = .Execute(sql)
Set wbk = Workbooks.Open(outputFilePath, , True)
Set wks = wbk.Sheets(outputSheetName)
wks.Cells(2, 1).CopyFromRecordset rs
wks.Columns.AutoFill
.Close
End With
End Sub
When I debug it highlights:
conn As New ADODB.Connection
I'm very new to Excel VBA and I don't know what it means.
Snippet of your code:
For Each filepath In Application.GetOpenFilename(FileFilter:="Excel Files (*.xl*), *.xl*", MultiSelect:=True)
'----------
Set schema = conn.OpenSchema(adSchemaTables) '<~~~ HERE YOU HAVE USED 'conn'
'----------
For Each sheetname In schema.GetRows(, , "TABLE_NAME") 'returns a 2D array of one column
sql = sql & _
"UNION ALL SELECT F1 " & _
"FROM [" & sheetname & "]" & _
"IN """ & filepath & """ ""Excel 12.0;"""
Next
Next
sql = Mid(sql, 5) 'Gets rid of the UNION ALL from the first SQL
'---------
Dim conn As New ADODB.Connection '<~~~ already exists, so duplicate declaration
'---------
Dim rs As ADODB.Recordset
With conn
As you can see from my comments, you have used conn
and then tried to dimension (Dim
) it, which is why you are getting the compile error.