Lets suppose I have the following list of maps
[{id:1,count:2,name:xyz},
{id:2,count:3,name:def},
{id:3,count:2,name:abc},
{id:4,count:5,name:ghj}
]
I first want to sort this map by count and then by name:
Desired Output :
[{id:3,count:2,name:abc},
{id:1,count:2,name:xyz},
{id:2,count:3,name:def},
{id:4,count:5,name:ghj}
]
I tried the following to perform the first sorting,but unable to sort using name after sorting by count
Collections.sort(list, new Comparator() {
public int compare(Object o1, Object o2) {
return ((Comparable) ((Map.Entry) (o1)).getValue())
.compareTo(((Map.Entry) (o2)).getValue());
}
With Java 1.8, I would use the new Comparator methods (although the lack of Type inference makes it necessary to declare all types, reducing the lisibility):
final Comparator<Map<String, Comparable<Object>>> nameThenCountComparator = Comparator.<Map<String, Comparable<Object>>, Comparable<Object>> comparing(
m -> m.get("name")).thenComparing(Comparator.<Map<String, Comparable<Object>>, Comparable<Object>> comparing(
m -> m.get("count")));
With Java 1.7, I would probably use a chainedComparator (see Apache's ComparatorUtils or Guava's Ordering) and a custom MapValueComparator (there are probably one in common libraries, but haven't found it). Then the wanted ordering get quite readable :
class MapValueComparator implements Comparator<Map<String, Object>> {
private final String key;
public MapValueComparator(final String key) {
this.key = key;
}
@Override
public int compare(final Map<String, Object> o1, final Map<String, Object> o2) {
return ((Comparable<Object>)o1.get(key)).compareTo(o2.get(key));
}
}
Comparator<Object> nameThenCountComparator = ComparatorUtils.chainedComparator(
new MapValueComparator("name"),
new MapValueComparator("count")
);
And then use it (Java 7 or 8):
final List<Map<String, Comparable<Object>>> list = null;
Collections.sort(list, nameThenCountComparator);
Rq: you should, as stated in other answers, check for nulls and absent keys in the MapValueComparator.