I have two data frames. The first (word.library) includes the strings which should match approximately the strings in the second data frame (targetframe).
word.library <- data.frame(mainword = c("important word",
"crazy sayings"))
tragetframe <- data.frame(words= c("Important Words",
"I would also Importante worde of thes substring",
"No mention of this crazy sayingsys"))
I only figured out the one by one solution (loops as well), however this does not satisfy my needs:
positions <- aregexec(word.library[1,1], tragetframe$words, max.distance = 0.1)
positions <- aregexec(word.library[2,1], tragetframe$words, max.distance = 0.1)
Finally: I´m looking for a solution to do this for all strings in column word.library$mainword at once. Has anyone a good idea? Thx.
find <- function(library.vec, frame.vec) {
aregexec(library.vec, frame.vec, max.distance = 0.1)
}
If a function is created from the expression that you tried, you will be able to include it in the apply family functions to repeat over the word library.
mapply(find, word.library[,1], list(tragetframe[,1]))
# [,1] [,2]
#[1,] 1 -1
#[2,] 14 -1
#[3,] -1 20
The attributes are dropped in the process. The output is arranged by column for each word. If you want to keep the attributes try:
lapply(word.library[,1], find, tragetframe[,1])