How to hide certain colors using spectrum color picker

Question

I am new to using Spectrum's color picker. So I looked through all functions spectrum-color picker had to offer, but I cannot find a way to hide some colors in the color picker so that users cannot select them.

E.g., all light colors: #FFFFFF, #F5F5F5, #FFFAFA, #F0FFF0, #F5FFFA, #F0FFFF, #F0F8FF, #F8F8FF, #FFF5E, #F5F5DC, #FDF5E6, #FFFAF0, #FFFFF0, #FAEBD7, #FAF0E6, #FFF0F5 shouldn't be available in the color picker.

Is there a way I can do this?

Answer 1

you have to make an array list with restricted color hax. then you should use change method in order to deal with. and jquery $.inArray() Function to determine restricted Color.

for example

var banColor = ['#ffffff','#000000','#F0FFF0', '#F5FFFA', '#F0FFFF', '#F0F8FF', '#F8F8FF', '#FFF5E', '#F5F5DC', '#FDF5E6', '#FFFAF0', '#FFFFF0', '#FAEBD7', '#FAF0E6', '#FFF0F5'];

$(".example").spectrum({
    color: "#f00",
    change: function(color) {
        if( $.inArray( color.toHexString(), banColor ) >= 0 ){
            $("#basic-log").text("change called: " + color.toHexString() +' Is Not Allowed');
            // Reset your palate
        }
    }
});