I want to get number present at the specific index.
Suppose the number is "123456789" and i need to return the number at position 3 from left.
Should I convert this number to a string and re-convert the char at specific index to integer to get the number value?
Is there any inbuilt function to do so in C++?
This should return the third digit that of a number!
cout << "Enter an integer";
int number;
cin >> number;
int n = number / 100 % 10
Or (for all digits):
int number = 12345;
int numSize = 5;
for (int i=numSize-1; i>=0; i--) {
int y = pow(10, i);
int z = number/y;
int x2 = number / (y * 10);
printf("%d-",z - x2*10 );
}