public boolean equals(Object o) {
if (this == o)
return true;
if ((o == null) || (this.getClass() != o.getClass()))
return false;
else {
AlunoTE umAluno = (AlunoTE) o;
return(this.nomeEmpresa.equals(umAluno.getNomeEmpresa()) && super.equals(umAluno);
}
}
Could anyone explain me how the fourth line ((this.getClass() != o.getClass())
) works when the argument is a super class? Because the classes have different names. this.getClass
will return a different name than o.getClass
, right?
Check the following code snippet which answers your question. Object O can hold any object. o.getClass() will return the run time class of the object
public class Main {
void method(Object o) {
System.out.println(this.getClass() == o.getClass());
}
public static void main(String[] args) {
new Main().method(new Object()); // false
new Main().method(new Main()); // true
new Main().method(new String()); // false
new Main().method(new MainOne()); // false
}
}
class MainOne extends Main
{
}