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jqueryjquery-ui-draggablejquery-ui-droppable

how to revert position of a jquery UI draggable based on condition


I have an element which is draggable and an element which is droppable. Once the dragged item is dropped on the dropzone I am trying to execute the following jquery psuedo code:

if(draggedelement == value){

$(draggedelement).hide();

}
else{

$(draggedelement).revert();

}

where the revert() function moves the dragged item back to its original postion.

How would one accomplish this?

P.S. I am aware of the draggable 'revert' option, however this only activates if the dragged item does not make it to the dropzone.


Solution

  • There are some built-in options for this, on your .draggable(), set the revert option to 'invalid', and it'll go back if it wasn't successfully dropped onto a droppable, like this:

    $("#draggable").draggable({ revert: 'invalid' });
    

    Then in your .droppable() set what's valid for a drop using the accept option, for example:

    $("#droppable").droppable({ accept: '#draggable' });​
    

    Anything not matching this selector gets reset when you let go, you can see a full demo here. The accept option also takes a function if you need filtering a selector can't provide, like this:

    $("#droppable").droppable({ 
      accept: function(dropElem) {
        //dropElem was the dropped element, return true or false to accept/refuse it
      }
    });​