Scanning values in C till hit a new-line char, '\n'

Question

How can I scanf() the integer values I enter into an array until I hit enter.

I believe I can use getchar() != '\n'.

but how do I loop through the line ?

Suppose my input is 20 21 2 12 2. I want an array that has all those inputs. What given functions could I use in order to scan them all in.

Answer 1

1. You are trying to read integers as characters so once read you need to convert it to integers.
2. Read the line to a buffer using fgets() then parse the input buffer to get integers.
3. Store the integers to the array.

The code looks like

char buf[300];
int a[5],i=0;
fgets(buf,sizeof(buf),stdin);
char *p = strtok(buf," ");
while(p != NULL)
{
  char *endptr;
  a[i] = strtol(p,&endptr,10);
  if ((*endptr != '\0') && (isspace(*endptr) == 0))
      printf("warning: invalid value detected\n");
  else
      i++;
  p = strtok(NULL," ");
}

You can use the alternative strtol() instead of atoi() to convert string to integer.

PS: Your buf should be large enough to hold the whole line. fgets() read till newline character.