i still try to change just 1 value on thish Script via js (remotePath), please give me informations :)
Thank you!
$('#uploader_div').ajaxupload(
{
url: 'upload.php',
dropArea: '#drop_here',
remotePath: 'user/user1/', <-- how to change only this value
...
like this
remotePath: 'user/user2/'
Update:
<div id="uploader_div"></div>
<a id="link" href="#" onclick="newvalue();"> Change user2 </a> <!--Change by Click-->
<script>
var uplobj = {
url: 'upload.php',
dropArea: '#drop_here',
remotePath: 'user/user1/', // Change by Click
autoStart: true,
hideUploadButton: true,
removeOnSuccess: true,
maxConnections: 0,
maxFileSize: '20M',
allowExt: ['mp3']
};
function newvalue()
{
uplobj.remotePath = 'user/user2/'; // Change by Click
link.style.display = 'none';
};
$('#uploader_div').ajaxupload(uplobj);
</script>
You can change an object anytime before the ajax call if you have a reference to it.
var obj = {
url: 'upload.php',
dropArea: '#drop_here',
remotePath: 'user/user1/'
};
obj.remotePath = 'user/user2/';
$('#uploader_div').ajaxupload(obj);
EDIT in response to more code
I read through the docs you are supposed to pass a standard jquery options object to ajaxupload. Right now you have a mix of jquery options and the data perhaps see the jquery docs for more info on what settings are valid.
A simple fix might be putting your current data in the data options attribute.
$('#uploader_div').ajaxupload({data: obj});