I try to multiply two BigDecimal Values with multiply methods as follows,
BigDecimal dur = BigDecimal.valueOf(60/1.1);
BigDecimal bal = BigDecimal.valueOf(1.1);
BigDecimal ans = dur.multiply(bal);
System.out.println("Ans:"+ans);
I am excepting ans as 60. But i got it as,
Ans:59.999999999999994
Why this comming and how can we resolve it.
The problem is you have a value which can't be represented in double but nor can it be represented in BigDecimal so you have to apply reasonable rounding to get the expected solution.
double d = 60 / 1.1 * 1.1;
System.out.println("double without rounding: " + d);
System.out.printf("double With rounding %.2f%n", d);
BigDecimal bd = BigDecimal.valueOf(60).divide(BigDecimal.valueOf(1.1), 9, BigDecimal.ROUND_HALF_UP).multiply(BigDecimal.valueOf(1.1));
System.out.println("BigDecimal without rounding: " + bd);
System.out.printf("BigDecimal with rounding %.2f%n", bd);
// or
bd = bd.setScale(2, BigDecimal.ROUND_HALF_UP);
System.out.println("BigDecimal with rounding: " + bd);
prints
double without rounding: 60.0
double With rounding 60.00
BigDecimal without rounding: 59.9999999995
BigDecimal with rounding 60.00
BigDecimal with rounding: 60.00
Note: double happens to round correctly for these values and gives the right answer. However, pick a different combination and it will be incorrect. e.g. 54.545454545454545 * 1.1 => 60.00000000000001