Search code examples
c++pass-by-pointer

passing a pointer to a built-in type defined on the fly in c++

I want to call a function of a library (that I can not modify)

void function(int* i, char* c);

Is there a way to call the function defining the int and the char on the fly?

i.e. doing something like

function(&1, &'v');

instead of

int int_1 = 1;
char char_1 = 'v';
function(&int_1, &char_v);

This would enormously decrease the length of my code while increasing readability.

Solution

  • As others have noted, the answer is no...

    You could simulate it by overloading function :

    void function(int i, char c)
{
  function(&i, &c);
}

    So now you can write function(1, 'v')