Catching an ArithmeticException but not handling as intended

Question

I am kinda new with the whole catching-handling exceptions concept and I was wondering why the throws ArithmeticException doesn't produce an exception error message (in this case/by zero) on exit, but instead during compilation.

Shouldn't it compile normally and then show the error message at the screen? What am I doing wrong?

public class Exception_Tester 
{ 
    public static void main(String args[]) 
    { 
         Exception_Tester et = new Exception_Tester(); 
         int x1; 
         int x2; 
         x1 = 5; 
         x2 = 0; 
         et.printResults(x1, x2); 
    } 

    void printResults(int a, int b) throws ArithmeticException 
    { 
         System.out.println("Add: "+(a+b)); 
         System.out.println("Sub: "+(a-b)); 
         System.out.println("Mul: "+(a*b));
         System.out.println("Div: "+(a/b));
    }  
} 

Answer 1

I executed your code as it is

public class Exception_Tester 
{ 
public static void main(String args[]) 
{ 
 Exception_Tester et = new Exception_Tester(); 
 int x1; 
 int x2; 
 x1 = 5; 
 x2 = 0; 
 et.printResults(x1, x2); 
} 
void printResults(int a, int b) throws ArithmeticException 
{ 
  System.out.println("Add: "+(a+b)); 
  System.out.println("Sub: "+(a-b)); 
  System.out.println("Mul: "+(a*b));
  System.out.println("Div: "+(a/b));
}  
} 

And it compiles fine without any error or exception, and as per your requirement, it is throwing ArithmeticException at run time only when System.out.println("Div: "+(a/b)); statement is encountered.

So I don't See any Problem there!